2^2x+128=3x2^x+1

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Solution for 2^2x+128=3x2^x+1 equation: 



2^2x+128=3x^2^x+1

We move all terms to the left:

2^2x+128-(3x^2^x+1)=0

We get rid of parentheses

-3x^2^x+2^2x-1+128=0

We add all the numbers together, and all the variables

-3x^2^x+2^2x+127=0

We move all terms containing x to the left, all other terms to the right

-3x^2^x+2^2x=-127

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